MATH SOLVE

3 months ago

Q:
# A box of 42 chocolates contains milk and dark chocolates in the ratio of 3:4. How many chocolates of each type there are?

Accepted Solution

A:

Answer:The number of milk chocolates are 18 and the number of dark chocolates are 24.Step-by-step explanation:Let the number of milk chocolates be [tex]m[/tex].Let the number of dark chocolates be [tex]d[/tex].Given that the box contains the milk and dark chocolates in the ratio [tex]3:4[/tex].So,[tex]\frac{m}{d}=\frac{3}{4}[/tex] ...(i)Given that the total number of chocolates are [tex]42[/tex].So,[tex]m+d=42[/tex]. ...(ii)Using (i) and (ii),[tex]m+\frac{4}{3}m=42[/tex][tex]\frac{7}{3}m=42[/tex][tex]m=18[/tex][tex]d=\frac{4}{3}m=\frac{4}{3}\times 18=24[/tex]So,the number of milk chocolates are [tex]18[/tex] and the number of dark chocolates are [tex]24[/tex].