MATH SOLVE

4 months ago

Q:
# Write the equation for a parabola that has x− intercepts (−1.6,0) and (−3.2,0) and y−intercept (0,25.6).

Accepted Solution

A:

x-intercepts are zeroes of the parabola.

(x-x1)(x-x2)=(x+1.6)(x+3.2)=x² +1.6x+3.2x+5.12=x²+4.8x+5.12

y=x²+4.8x+5.12, but the y-int. is (0, 25.6),

So, our parabola should look like

y=5(x²+4.8x+5.12)

y=5x²+24x+25.6

(x-x1)(x-x2)=(x+1.6)(x+3.2)=x² +1.6x+3.2x+5.12=x²+4.8x+5.12

y=x²+4.8x+5.12, but the y-int. is (0, 25.6),

So, our parabola should look like

y=5(x²+4.8x+5.12)

y=5x²+24x+25.6